Okay, having read all pertaining info to modding the srec I think I have this but wanted to make sure I have it down.

My MCS2000 is a 160 channel Model III unit, I wish to make it a 250 channel unit and I assume the radio can do that with just a couple hex changes to the srec.

My FDB reads like this:

S11F01F8000000000000000022101916D2197EF2D924FB00C24400004840104055

S11F0214000000C0000030A006000008000000DB00000000000000000000000051

SO to mod from 160 to 250 I must change Offset 27 from A0h to FAh which is 160 to 250 channels

and change Offset 29 so that 250 modes are enabled-

Offset 29:

7 6 5 4 3 2 1 0

0 0 0 0 0 0 0 0

7 - Unused

6 - Unused

5 - H260 250 Mode Capability (Models II & III)

4 - Unused

3 - Unused

2 - Unused

1 - H451 GE Star

0 - H169 Quik Call II Decode/Singletone/Repeater Access

therefore:

I change A0h to FAh at offset 27 and also change 00h to 20h (which is 0010000) at offset 29 and then correct the end of line checksum, which before making any changes is DBh.

so FAh-A0h= 5Ah and 20h-00h= 20 so therefore:

5Ah + 20h= 7Ah which must be subtracted from the end of line checksum above of DBh

so 7Ah-DBh= so the new checksum is 9Fh?

Or would it be 61h?

I was hoping that someone could doublecheck my hex math as I think I have the math incorrect, and that's the frustrating part.

Any guidance appreciated!

My MCS2000 is a 160 channel Model III unit, I wish to make it a 250 channel unit and I assume the radio can do that with just a couple hex changes to the srec.

My FDB reads like this:

S11F01F8000000000000000022101916D2197EF2D924FB00C24400004840104055

S11F0214000000C0000030A006000008000000DB00000000000000000000000051

SO to mod from 160 to 250 I must change Offset 27 from A0h to FAh which is 160 to 250 channels

and change Offset 29 so that 250 modes are enabled-

Offset 29:

7 6 5 4 3 2 1 0

0 0 0 0 0 0 0 0

7 - Unused

6 - Unused

5 - H260 250 Mode Capability (Models II & III)

4 - Unused

3 - Unused

2 - Unused

1 - H451 GE Star

0 - H169 Quik Call II Decode/Singletone/Repeater Access

therefore:

I change A0h to FAh at offset 27 and also change 00h to 20h (which is 0010000) at offset 29 and then correct the end of line checksum, which before making any changes is DBh.

so FAh-A0h= 5Ah and 20h-00h= 20 so therefore:

5Ah + 20h= 7Ah which must be subtracted from the end of line checksum above of DBh

so 7Ah-DBh= so the new checksum is 9Fh?

Or would it be 61h?

I was hoping that someone could doublecheck my hex math as I think I have the math incorrect, and that's the frustrating part.

Any guidance appreciated!

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